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Figure 9.1 below shows a gear drive system - NSC Mechanical Technology Fitting and Machining - Question 9 - 2018 - Paper 1

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Figure 9.1 below shows a gear drive system. Driver gear A on the shaft of the electric motor has 40 teeth that mesh with gear B with 60 teeth on a counter shaft. On ... show full transcript

Worked Solution & Example Answer:Figure 9.1 below shows a gear drive system - NSC Mechanical Technology Fitting and Machining - Question 9 - 2018 - Paper 1

Step 1

9.1.1 Rotation frequency of the final driven shaft if the electrical motor rotates at 1 440 r/min

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Answer

To calculate the rotation frequency of the final driven shaft, we can use the relationship between the gears. The formula is:

ND=NA×TA×TCTB×TDN_D = \frac{N_A \times T_A \times T_C}{T_B \times T_D}

Where:

  • NDN_D = rotation frequency of the final driven shaft
  • NAN_A = rotation frequency of the electrical motor = 1440 r/min
  • TAT_A = number of teeth on gear A = 40
  • TBT_B = number of teeth on gear B = 60
  • TCT_C = number of teeth on gear C = 30
  • TDT_D = number of teeth on gear D = 80

Substituting the values:

ND=(40×30×1440)(60×80)N_D = \frac{(40 \times 30 \times 1440)}{(60 \times 80)}

Calculating this, we find:

ND=360r/minN_D = 360 \, \text{r/min}

Step 2

9.1.2 Velocity ratio between the input and output shafts

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Answer

The velocity ratio (VR) can be calculated using the formula:

VR=NinputNoutputVR = \frac{N_{input}}{N_{output}}

Here, the input speed is that of the electrical motor at 1440r/min1440 \, \text{r/min} and the output speed is that of the final driven shaft calculated as 360r/min360 \, \text{r/min}.

Substituting the values:

VR=1440360=4:1VR = \frac{1440}{360} = 4:1

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