11.1.1 Die vloestofdruk in die hidrouliese stelsel is in MPa
P = F / A
Hier is F = 25 kN = 25 × 10^3 N - NSC Mechanical Technology Fitting and Machining - Question 11 - 2021 - Paper 1
Question 11
11.1.1 Die vloestofdruk in die hidrouliese stelsel is in MPa
P = F / A
Hier is F = 25 kN = 25 × 10^3 N.
Die oppervlakte (A) van die plunjer is:
A = πd² / 4
w... show full transcript
Worked Solution & Example Answer:11.1.1 Die vloestofdruk in die hidrouliese stelsel is in MPa
P = F / A
Hier is F = 25 kN = 25 × 10^3 N - NSC Mechanical Technology Fitting and Machining - Question 11 - 2021 - Paper 1
Step 1
Die vloestofdruk in die hidrouliese stelsel is in MPa
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Die druk kan bereken word met die formule:
P = rac{F}{A}
waar F die krag van 25 kN of 25 × 10³ N is. Die oppervlakte (A) van die plunjer word bereken as:
A = rac{ ext{π}d²}{4} = rac{ ext{π}(0.035)²}{4} = 9.62 × 10^{-7} m²
Hierna kan ons die druk P bereken:
P = rac{25 × 10³}{9.62 × 10^{-7}} = 25.98 MPa
Step 2
Die grootte van die krag wat deur die ram op die lier uitgeoefen sal word
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Bereken die oppervlakte (A) van die ram:
A = rac{ ext{π}D²}{4} = rac{ ext{π}(0.120)²}{4} = 11.31 × 10^{-3} m²
Die krag (F) wat deur die ram op die lier uitgeoefen word, kan bereken word met:
F=P×A=25.98×106imes11.31×10−3=293.92kN
Step 3
NOEM EEN funksie van 'n hidrouliese reservoir
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Opgaartenk
Step 4
GEE TWEE redes waarom pneumatiese stelsels baie effektief is
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Bewegingstyd is vinniger.
Minder krag benodig.
Step 5
NOEM TWEE gebruike van pneumatiese stelsels
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Lugsulptoerusting
Klopboor (jackhammer)
Step 6
Die rotasiefrekvensie van die katrol op die wasmasjien in r/s
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Die rotasiefrekvensie kan bereken word deur die verhouding van die diameters te gebruik:
N2 = N1 × rac{D1}{D2}
N2 = 7.2 × rac{0.6}{0.8} = 5.4 r/s
Step 7
Die drywing wat oorgedra kan word in kW
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Gebruik die formule:
P = (T1 - T2) × rac{ ext{π}}{DN}
Bereken die drywing wat oorgedra kan word:
P=(300−120)×extπ×5.4=2442.90Watt=2.44kW
Step 8
Die rotasiefrekvensie van die leweringsas indien die motor teen 2300 min rotore
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Gebruik die relasie:
N1×D1=N2×D2
Daarmee kan ons die rotasiefrekvensie bereken:
N2 = N1 × rac{D1}{D2}
N2 = 7.2 × rac{40}{30} = 9.6 r/s
Step 9
Die ratverhouding
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Die ratverhouding kan bereken word as:
ext{Ratverhouding} = rac{ ext{Produk van tande op gedrewe rate}}{ ext{Produk van tande op dryfrate}}
