A steel ring must be manufactured using a 60 × 60 mm square steel bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2021 - Paper 1
Question 5
A steel ring must be manufactured using a 60 × 60 mm square steel bar. The ring has an outside diameter of 960 mm.
5.1.1 Calculate the mean diameter of the ring.
5... show full transcript
Worked Solution & Example Answer:A steel ring must be manufactured using a 60 × 60 mm square steel bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2021 - Paper 1
Step 1
5.1.1 Calculate the mean diameter of the ring.
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Answer
To calculate the mean diameter of the ring, we subtract the thickness of the steel bar from the outside diameter:
Mean Diameter = Outside Diameter - Plate Thickness
Mean Diameter = 960 mm - 60 mm = 900 mm.
Step 2
5.1.2 Calculate the mean circumference of the ring (round off answer to the nearest whole number).
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Answer
The mean circumference can be calculated using the formula:
Mean Circumference = π × Mean Diameter
Mean Circumference = π × 900 mm ≈ 2827.43 mm.
After rounding to the nearest whole number, the mean circumference is 2827 mm.
Step 3
5.2.1 Spot weld
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The symbol for a spot weld is a dot on the reference line, indicating where the weld is applied.
Step 4
5.2.2 Projection weld
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The symbol for a projection weld is represented by a series of triangles on the reference line, indicating the locations of the projections.
Step 5
5.2.3 Seam weld
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The seam weld symbol consists of a zigzag line across the reference line, indicating a continuous type of weld.
Step 6
5.2.4 Foil seam weld
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The foil seam weld is represented by a wavy line on the reference line, indicating a weld that is applied to the edges of two sheets.
Step 7
5.2.5 Flash or resistance weld
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The flash or resistance weld symbol is shown as a line with small circles indicating the points where the weld is applied.
Step 8
5.3 Identify the templates shown in FIGURES 5.3.1–5.3.3 below.
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