A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth - NSC Mechanical Technology Welding and Metalwork - Question 9 - 2016 - Paper 1
Question 9
A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth. There is a driver gear with 40 teeth on t... show full transcript
Worked Solution & Example Answer:A driver gear on the shaft of an electrical motor has 30 teeth and meshes with a gear on a countershaft which has 80 teeth - NSC Mechanical Technology Welding and Metalwork - Question 9 - 2016 - Paper 1
Step 1
9.1.1 The rotation frequency of the electrical motor
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Answer
To find the rotation frequency of the electrical motor, we can use the following formula:
N_a = rac{T_b imes N_d}{T_a \times T_c}
Where:
Tb = Number of teeth on driven gear = 80
Ta = Number of teeth on driver gear = 30
Nd = Speed of driven gear = 2 r.s-1
Tc = Number of teeth on the counter shaft gear = 40
Substituting the values:
Na=30×4080×2=8.4
The rotation frequency of the electrical motor is therefore: Na=1200 rev/min (or 20 r.p.s).
Step 2
9.1.2 The speed ratio of the gear train
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Answer
The speed ratio can be calculated as follows:
Speed ratio=OutputInput
Where:
Input = 80 (driven teeth)
Output = 30 (driver teeth)
Substituting the values gives:
Speed ratio=3080=2.67:1
This indicates that for every 2.67 rotations of the driver gear, the driven gear makes 1 rotation.
Step 3
9.2.1 The rotational frequency of the pulley on the washing machine
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Answer
The rotational frequency of the driven pulley can be derived using the gearbox ratio:
N1×D1=N2×D2
Where:
N1 = Rotational frequency of washing machine pulley
D1 = Diameter of washing machine pulley = 600 mm
N2 = Rotational frequency of driven pulley = 7.2 r.s-1
D2 = Diameter of driven pulley = 800 mm
Rearranging the equation yields:
N1=D1N2×D2=6007.2×800=9.6r.s−1
Step 4
9.2.2 The power that can be transmitted
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Answer
To find the power transmitted, we can use the formula:
P=(T1−T2)×F
Where:
T1 = Force in tight side of the belt = 300 N
T2 = Tension in the slack side of the belt = 120 N
F = Factor of rotation = 7.2
From the tension values, calculating gives:
P=(300−120)×7.2=1296Watt
This shows the power that can be transmitted by the pulley system.
Step 5
9.3 How can the volume of a certain mass of gas be changed?
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Answer
The volume of a certain mass of gas can be changed through its pressure and temperature. Adjusting these two variables allows for expansion or compression, changing the volume of the gas while keeping the mass constant.
Step 6
9.4 Define Boyle's law with reference to gases
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Answer
Boyle's law states that the volume of a given mass of gas is inversely proportional to the pressure exerted on it, provided the temperature remains constant. This means as the pressure increases, the volume decreases, and vice versa.
Step 7
9.5.1 The fluid pressure in the hydraulic system when in equilibrium
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Answer
The fluid pressure can be calculated using the area and the force applied:
P=AF
Where:
F = Applied load = 320 N
A = Area of piston A = π(0.04m)2/4
Calculating gives:
P=AA320
Thus, the pressure in the hydraulic system is determined based on the area of piston A.
Step 8
9.5.2 The diameter of piston B
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Answer
To find the diameter of piston B, we start with:
PB=PA
From the equilibrium of forces:
We know FB=FA.
Then use:
A=PF
From the values of forces and pressure calculated, determine:
DB=π4AB
This will yield the diameter of the piston B.