SimpleStudy Schools Book a Demo We can give expert advice on our plans and what will be the best option for your school.
Parents Pricing Home NSC Mechanical Technology Welding and Metalwork Developments and templates A brass ring must be manufactured using a 30 x 30 mm square bar
A brass ring must be manufactured using a 30 x 30 mm square bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2023 - Paper 1 Question 5
View full question A brass ring must be manufactured using a 30 x 30 mm square bar. The ring has an inside diameter of 870 mm.
Calculate the following:
5.1.1 The mean diameter of the... show full transcript
View marking scheme Worked Solution & Example Answer:A brass ring must be manufactured using a 30 x 30 mm square bar - NSC Mechanical Technology Welding and Metalwork - Question 5 - 2023 - Paper 1
5.1.1 The mean diameter of the ring Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
To calculate the mean diameter of the ring, we utilize the formula:
e x t M e a n D i a m e t e r = e x t I n s i d e D i a m e t e r + e x t P l a t e T h i c k n e s s ext{Mean Diameter} = ext{Inside Diameter} + ext{Plate Thickness} e x t M e an D iam e t er = e x t I n s i d eD iam e t er + e x t Pl a t e T hi c kn ess
Here, the inside diameter is 870 mm, and assuming the plate thickness of the square bar is 30 mm, we have:
e x t M e a n D i a m e t e r = 870 + 30 = 900 e x t m m ext{Mean Diameter} = 870 + 30 = 900 ext{ mm} e x t M e an D iam e t er = 870 + 30 = 900 e x t mm
Thus, the mean diameter of the ring is 900 mm .
5.1.2 The mean circumference of the ring Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The formula for calculating the mean circumference is:
e x t M e a n C i r c u m f e r e n c e = e x t π i m e s e x t M e a n D i a m e t e r ext{Mean Circumference} = ext{π} imes ext{Mean Diameter} e x t M e an C i rc u m f ere n ce = e x t π im ese x t M e an D iam e t er
Substituting the mean diameter obtained:
e x t M e a n C i r c u m f e r e n c e = e x t π i m e s 900 e x t m m e x t a p p r o x i m a t e l y = 2827.43 e x t m m ext{Mean Circumference} = ext{π} imes 900 ext{ mm} \\ ext{approximately} = 2827.43 ext{ mm} e x t M e an C i rc u m f ere n ce = e x t π im es 900 e x t mm e x t a pp ro x ima t e l y = 2827.43 e x t mm
Rounding off to the nearest whole number, the mean circumference is 2827 mm .
5.2.1 Square butt Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The fusion weld symbol for a square butt joint is represented as:
||
5.2.2 V-groove Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The fusion weld symbol for a V-groove joint is represented as:
V
5.2.3 U-butt Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The fusion weld symbol for a U-butt joint is represented as:
U
5.2.4 J-butt Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The fusion weld symbol for a J-butt joint is represented as:
J
5.2.5 Flare V Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The fusion weld symbol for a flare V joint is represented as:
\/
5.3.1 Identify the type of joint. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
The type of joint shown in FIGURE 5.3 is a T-joint .
5.3.2 Identify labels A–G. Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Based on FIGURE 5.3, the identification of labels is as follows:
A - weld all around
B - Site weld
C - Fillet weld
D - Tail
E - Pitch of weld
F - Length of weld
G - Size of weld
Join the NSC students using SimpleStudy...97% of StudentsReport Improved Results
98% of StudentsRecommend to friends
100,000+ Students Supported
1 Million+ Questions answered
;© 2025 SimpleStudy. All rights reserved