11.1 Ware lengte CG Die ware lengte FG: IK = 300 (2 eenhede) IH = 150 (1 eenheid) HK = 1/3 (1 eenheid) / √3 Die ware lengte FG is gelijk aan H’F - NSC Mechanical Technology Welding and Metalwork - Question 11 - 2020 - Paper 1

The next step is to find the lengths CE and EI in triangle CEI: For CE: $CE = CF - EF$ Given EF = 150, we have:

$CE = 400 - 150 = 250mm$

Next, for EI: Using the relationship for HK: $HK = 150 / √3 = 259.81mm$ We then find: $FH = FK - HK = 400 - 259.81 = 140,19mm$

Now we can calculate CI: $CI^2 = CE^2 + EI^2$

Substituting our values in:

• $CE = 250mm$
• $EI = 140.19mm$

Then using the Pythagorean theorem: $CI = \sqrt{C'I^2 + (Loodregte hoogte)^2}$ Finally, we find CI to be approximately 849.79 mm.

To find the length JI as a twelfth of the perimeter, we use the formula:

$JI = \frac{ ext{Omtrek}}{12}$

If the perimeter (Omtrek) is given as 1884.9, Then: $JI = \frac{1884,9}{12} \\ ≈ 157,08mm$