FIGURE 9.1 shows a belt-drive system with a 230 mm driver pulley - NSC Mechanical Technology Welding and Metalwork - Question 9 - 2016 - Paper 1

The power transmitted can be calculated using the following formula:

$P = (T_t - T_s) \times V$

Where:

• $T_t$ is the tension in the tight side (350 N)
• $T_s$ is the tension in the slack side (140 N)
• $V$ is the belt speed (36 m/s)
• $T_t = 2.5 \times T_s$

First, calculate $T_t$:

$T_t = 2.5 \times 140 = 350 N$

Now substituting the values into the power equation:

$P = (350 - 140) \times 36 = 7560 \text{ W}$

Therefore, the transmitted power is approximately 7.56 kW.