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Vier trekkragte van 1,2 kN, 2 kN, 3,4 kN en 1,8 kN werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2017 - Paper 1

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Vier-trekkragte-van-1,2-kN,-2-kN,-3,4-kN-en-1,8-kN-werk-op-dieselfde-punt-in,-soos-in-FIGUUR-7.1-hieronder-getoon-NSC Mechanical Technology Welding and Metalwork-Question 7-2017-Paper 1.png

Vier trekkragte van 1,2 kN, 2 kN, 3,4 kN en 1,8 kN werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon. Bepaal, met behulp van berekeninge, die grootte en... show full transcript

Worked Solution & Example Answer:Vier trekkragte van 1,2 kN, 2 kN, 3,4 kN en 1,8 kN werk op dieselfde punt in, soos in FIGUUR 7.1 hieronder getoon - NSC Mechanical Technology Welding and Metalwork - Question 7 - 2017 - Paper 1

Step 1

Kragkomponente Berekening

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Answer

Bereken die horisontale en vertikale komponente van elke trekkrag:

  1. Vir 3,4 kN:

    • Horisontaal: 3,4=3,4kN3,4 = 3,4 kN (alleenlik)
    • Vertikaal: 0kN0 kN
  2. Vir 1,2 kN:

    • Horisontaal: 1,2cos(40)1,2 \cos(40^{\circ})
    • Vertikaal: 1,2sin(40)1,2 \sin(40^{\circ})
  3. Vir 2 kN:

    • Horisontaal: 2cos(50)2 \cos(50^{\circ})
    • Vertikaal: 2sin(50)2 \sin(50^{\circ})
  4. Vir 1,8 kN:

    • Horisontaal: 1,8cos(70)1,8 \cos(70^{\circ})
    • Vertikaal: 1,8sin(70)1,8 \sin(70^{\circ})

Step 2

Totale Horizontal en Vertikale Kragte

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Answer

Som alle horisontale en vertikale komponente op:

  • Totale Horisontale Krag: extHK=3,4+1,2cos(40)+2cos(50)+1,8cos(70) ext{HK} = 3,4 + 1,2 \cos(40^{\circ}) + 2 \cos(50^{\circ}) + 1,8 \cos(70^{\circ})
  • Totale Vertikale Krag: extVK=1,2sin(40)+2sin(50)1,8sin(70) ext{VK} = 1,2 \sin(40^{\circ}) + 2 \sin(50^{\circ}) - 1,8 \sin(70^{\circ})

Step 3

Resultant Berekening

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Answer

Berekend die grootte van die resultant: R=HK2+VK2R = \sqrt{\text{HK}^{2} + \text{VK}^{2}}

Bepaal die hoek met: tan(θ)=VKHK\tan(\theta) = \frac{\text{VK}}{\text{HK}}

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