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7.1 The conductivity of three acid solutions, A, B and C, as shown below is investigated at the same temperature - NSC Physical Sciences - Question 7 - 2023 - Paper 2

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7.1 The conductivity of three acid solutions, A, B and C, as shown below is investigated at the same temperature. A 0,1 mol·dm⁻³ H₂SO₄(aq) B 0,1 mol·dm⁻³ HNO₃(a... show full transcript

Worked Solution & Example Answer:7.1 The conductivity of three acid solutions, A, B and C, as shown below is investigated at the same temperature - NSC Physical Sciences - Question 7 - 2023 - Paper 2

Step 1

Define the term electrolyte.

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Answer

An electrolyte is a substance that dissociates into ions in solution, thus conducting electricity. It typically consists of acids, bases, or salts that, when dissolved in water, allow for the movement of charged particles.

Step 2

In which solution, A or B, will the bulb be brighter? Give a reason for the answer by referring to the types of acids.

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Answer

The bulb will be brighter in solution A (H₂SO₄) because sulfuric acid is a strong acid and it is diprotic, meaning it donates two protons (H⁺ ions) per molecule. This results in a higher concentration of ions in solution, which enhances its conductivity compared to HNO₃, which is monoprotic and donates only one H⁺ ion.

Step 3

In which solution, B or C, will the bulb be brighter? Give a reason for the answer by referring to the types of acids.

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Answer

The bulb will be brighter in solution B (HNO₃) compared to solution C (CH₃COOH) because HNO₃ is a strong acid and fully dissociates in solution, producing a higher concentration of ions. In contrast, acetic acid (CH₃COOH) is a weak acid and does not fully dissociate, resulting in fewer ions in solution and, therefore, lower conductivity.

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