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10.1 A simplified sketch of an AC generator is shown below - NSC Physical Sciences - Question 10 - 2016 - Paper 1

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10.1 A simplified sketch of an AC generator is shown below. Coil A Pole piece of magnet The coil of the generator rotates clockwise between the pole pieces of t... show full transcript

Worked Solution & Example Answer:10.1 A simplified sketch of an AC generator is shown below - NSC Physical Sciences - Question 10 - 2016 - Paper 1

Step 1

10.1.1 Identify the magnetic pole A.

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Answer

The magnetic pole A is the NORTH POLE.

Step 2

10.1.2 The coil is rotated through 180°.

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Answer

When the coil is rotated through 180°, the direction of the current in segment PQ will change from P to Q.

Step 3

10.2.1 Resistance of the device

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Answer

To calculate the resistance (R) of the device, we use Ohm's Law:

R=VrmsIrmsR = \frac{V_{rms}}{I_{rms}}

Given that the rms voltage (V_{rms}) is 220 V and the rms current (I_{rms}) is 8 A:

R=220V8A=27.5ΩR = \frac{220 V}{8 A} = 27.5 \Omega

Step 4

10.2.2 Energy the device consumes in two hours

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Answer

The energy (E) consumed can be calculated using the formula:

E=PtE = P \cdot t

First, we need to calculate the power (P):

P=VrmsIrms=220V8A=1760WP = V_{rms} \cdot I_{rms} = 220 V \cdot 8 A = 1760 W

Now, we convert two hours into seconds:

t=23600=7200st = 2 \cdot 3600 = 7200 s

Now, substituting the values to find the energy consumed:

E=1760W7200s=12672000JE = 1760 W \cdot 7200 s = 12672000 J

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