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9.1 When the coil of the generator rotates clockwise between the two poles of the magnet, the direction of the induced current is from X to Y, as shown above - NSC Physical Sciences - Question 9 - 2023 - Paper 1

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9.1 When the coil of the generator rotates clockwise between the two poles of the magnet, the direction of the induced current is from X to Y, as shown above. 9.1.1... show full transcript

Worked Solution & Example Answer:9.1 When the coil of the generator rotates clockwise between the two poles of the magnet, the direction of the induced current is from X to Y, as shown above - NSC Physical Sciences - Question 9 - 2023 - Paper 1

Step 1

9.1.1 Is A the NORTH POLE or the SOUTH POLE of the magnet?

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Answer

A is the NORTH POLE of the magnet. This conclusion is drawn from the direction of the current induced in the coil when it rotates clockwise.

Step 2

9.1.2 The coil is now rotated through 180°.

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Answer

After rotating the coil through 180°, the direction of the magnetic field concerning the coil reverses, affecting the induced current direction.

Step 3

9.1.3 Will the direction of the current be from X to Y or from Y to X?

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Answer

The direction of the current will reverse to go from Y to X after the coil rotates 180°.

Step 4

9.2.1 Resistance of the device

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Answer

To calculate the resistance (R) of the device, use the formula:

R=VrmsIrmsR = \frac{V_{rms}}{I_{rms}}

Given:

  • Vrms=200 VV_{rms} = 200 \ V
  • Irms=6 AI_{rms} = 6 \ A

Substituting the values:

R=200 V6 A=33.33ΩR = \frac{200 \ V}{6 \ A} = 33.33 \Omega

Step 5

9.2.2 Energy consumed by the device in two hours

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Answer

The energy (W) consumed can be calculated using the formula:

W=Vrms×Irms×tW = V_{rms} \times I_{rms} \times t

Where:

  • t=2 hours=7200 secondst = 2 \ hours = 7200 \ seconds

Substituting the values:

W=200 V×6 A×7200 s=8640000 JW = 200 \ V \times 6 \ A \times 7200 \ s = 8640000 \ J

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