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5.1 A submarine can use the Doppler effect to detect the speed of the ship - NSC Physical Sciences - Question 5 - 2016 - Paper 1

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5.1 A submarine can use the Doppler effect to detect the speed of the ship. A submarine at rest and just below the surface of the water, detects the frequency of a m... show full transcript

Worked Solution & Example Answer:5.1 A submarine can use the Doppler effect to detect the speed of the ship - NSC Physical Sciences - Question 5 - 2016 - Paper 1

Step 1

State Doppler effect in words.

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Answer

The Doppler effect refers to the apparent change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. It causes the frequency of the sound to be perceived as higher when the source approaches and lower when it retreats.

Step 2

Is the ship moving away from or towards the submarine? Give a reason for your answer.

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Answer

The ship is moving away from the submarine. This is because the detected frequency of sound (437 Hz) is lower than the actual frequency emitted by the ship. According to the Doppler effect, a decrease in frequency indicates that the source is moving away from the observer.

Step 3

Calculate the speed of the ship.

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Answer

To calculate the speed of the ship, we can use the formula for the Doppler effect:

FL=FSv+vLv+vSF_L = F_S \frac{v + v_L}{v + v_S}

Where:

  • FLF_L = observed frequency (437 Hz)
  • FSF_S = actual frequency (calculated as FL/0.985F_L / 0.985)
  • vv = speed of sound in water (1470 m/s)
  • vLv_L = speed of the listener (0 m/s, since the submarine is at rest)
  • vSv_S = speed of the source (the ship, which we need to calculate)
  1. Calculate the actual frequency: FS=FL0.985=4370.985443.65 HzF_S = \frac{F_L}{0.985} = \frac{437}{0.985} \approx 443.65 \text{ Hz}

  2. Now we can rearrange the formula to find the speed of the source: FL=FSvv+vSF_L = F_S \frac{v}{v + v_S} Rearranging gives us: FL(v+vS)=FSvF_L (v + v_S) = F_S v FLv+FLvS=FSvF_L v + F_L v_S = F_S v FLvS=FSvFLvF_L v_S = F_S v - F_L v vS=(FSFL)vFLv_S = \frac{(F_S - F_L)v}{F_L} Plugging in the values: vS=(443.65437)×147043722.39 m/sv_S = \frac{(443.65 - 437) \times 1470}{437} \approx 22.39 \text{ m/s}

Step 4

Explain how the phenomenon known as red shift can be used to explain an expanding universe.

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Answer

The red shift phenomenon occurs when light from distant galaxies is stretched to longer wavelengths as they move away from us. This stretching indicates that the universe is expanding. By measuring the red shift of light from galaxies, astronomers can determine how fast those galaxies are receding. The greater the red shift, the faster the galaxy is moving away, which supports the theory that the universe is expanding over time.

Step 5

Does the spectrum of the other galaxy constitute a RED SHIFT or BLUE SHIFT?

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Answer

The spectrum of the other galaxy constitutes a RED SHIFT. If absorption lines in the spectrum are moved towards the red end, it indicates that the galaxy is moving away from us, thus demonstrating a red shift.

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