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When light of various frequencies is incident on the metal cathode of a photocell, photoelectrons are emitted from the surface of the cathode - NSC Physical Sciences - Question 10 - 2021 - Paper 1

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Question 10

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When light of various frequencies is incident on the metal cathode of a photocell, photoelectrons are emitted from the surface of the cathode. The graph below shows... show full transcript

Worked Solution & Example Answer:When light of various frequencies is incident on the metal cathode of a photocell, photoelectrons are emitted from the surface of the cathode - NSC Physical Sciences - Question 10 - 2021 - Paper 1

Step 1

Use the graph to determine the maximum kinetic energy of the emitted photoelectron when the wavelength of the incident light is 1.0 x 10^-7 m.

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Answer

From the graph, locate the point where the wavelength is 1.0 x 10^-7 m. The corresponding value of the maximum kinetic energy (E_k(max)) at this wavelength is approximately 14.0 x 10^-19 J.

Step 2

What relationship between the maximum kinetic energy of the emitted photoelectron and the wavelength of the incident light can be deduced from the graph?

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Answer

The maximum kinetic energy of the emitted photoelectron is inversely proportional to the wavelength of the incident light. This means that as the wavelength increases, the maximum kinetic energy decreases.

Step 3

Define the term work function in words.

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Answer

The work function is the minimum energy required to remove an electron from the surface of a material. It represents the energy barrier that must be overcome for an electron to be emitted.

Step 4

Use the graph to calculate the work function of the metal used as cathode of this photocell.

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Answer

To find the work function (W_0), use the formula: E = W_0 + E_k(max). Using the maximum kinetic energy from part 10.1 (14.0 x 10^-19 J) and the value of E for the wavelength of light corresponding to the threshold frequency, we calculate W_0. For instance, using a wavelength of 4.0 x 10^-7 m producing E of approximately 4.06 x 10^-19 J yields: W_0 = E - E_k(max) = 4.06 x 10^-19 J - 14.0 x 10^-19 J = -9.94 x 10^-19 J.

Step 5

Calculate the maximum kinetic energy of the emitted photoelectron when the wavelength of the incident light is 0.5 x 10^-7 m.

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Answer

Using the graph, find the value of E_k(max) corresponding to a wavelength of 0.5 x 10^-7 m. The maximum kinetic energy at this wavelength is approximately 16.0 x 10^-19 J.

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