Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface. The following graphs show the net force experienced by each object respectively during the same time interval. **Graph for Object P:** ![Graph for Object P] **Graph for Object Q:** ![Graph for Object Q] 9.1 Calculate the total impulse experienced by object Q in 10 s. 9.2 Compare without using any calculations the total impulse for object P with that of object Q. Write down only GREATER THAN, LESS THAN or EQUAL TO. 9.3 Calculate the final velocity of object Q.

NSC Physical Sciences Momentum and Impulse: Two identical objects P and Q wi

Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface - NSC Physical Sciences - Question 9 - 2016 - Paper 1

Question 9

Two-identical-objects-P-and-Q-with-a-mass-of-10-kg-each,-are-moving-side-by-side-with-an-initial-velocity-of-5,5-m·s⁻¹-east-on-a-horizontal-surface-NSC Physical Sciences-Question 9-2016-Paper 1.png

Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface. The following gr... show full transcript

Worked Solution & Example Answer:Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface - NSC Physical Sciences - Question 9 - 2016 - Paper 1

Step 1

9.1 Calculate the total impulse experienced by object Q in 10 s.

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Answer

To calculate the total impulse experienced by object Q, we need to find the area under the graph for Object Q over the time interval of 10 seconds.

From the graph, the net force experienced by Object Q is constant at 10 N for the first 10 seconds. Therefore, the impulse can be calculated using the formula:

$ext{Impulse} = ext{Area} = ext{Force} imes ext{Time} = 10 ext{ N} imes 10 ext{ s} = 100 ext{ N·s}$

Thus, the total impulse experienced by object Q in 10 seconds is 100 N·s.

Step 2

9.2 Compare without using any calculations the total impulse for object P with that of object Q. Write down only GREATER THAN, LESS THAN or EQUAL TO.

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Answer

The total impulse experienced by object P is GREATER THAN that of object Q because the area under the graph for Object P is larger than that for Object Q.

Step 3

9.3 Calculate the final velocity of object Q.

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Answer

To find the final velocity of object Q, we use the impulse-momentum theorem:

$ext{Impulse} = m(v_f - v_i)$

Where:

Impulse = 100 N·s (from Step 9.1)
m = 10 kg (mass of object Q)
$v_i$ = 5.5 m·s⁻¹ (initial velocity)

Substituting the known values:

$100 = 10(v_f - 5.5)$

Dividing by 10: $10 = v_f - 5.5$

Solving for $v_f$ : $v_f = 10 + 5.5 = 6.5 ext{ m·s}^{-1}$

Therefore, the final velocity of object Q is 6.5 m·s⁻¹.

Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface - NSC Physical Sciences - Question 9 - 2016 - Paper 1

Worked Solution & Example Answer:Two identical objects P and Q with a mass of 10 kg each, are moving side by side with an initial velocity of 5,5 m·s⁻¹ east on a horizontal surface - NSC Physical Sciences - Question 9 - 2016 - Paper 1

9.1 Calculate the total impulse experienced by object Q in 10 s.

9.2 Compare without using any calculations the total impulse for object P with that of object Q. Write down only GREATER THAN, LESS THAN or EQUAL TO.

9.3 Calculate the final velocity of object Q.

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