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3.1 Define the term boiling point - NSC Physical Sciences - Question 3 - 2019 - Paper 2

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3.1 Define the term boiling point. 3.2 Give a reason why this is a fair comparison. The boiling points of compounds Q, R and S are given below (NOT necessarily in ... show full transcript

Worked Solution & Example Answer:3.1 Define the term boiling point - NSC Physical Sciences - Question 3 - 2019 - Paper 2

Step 1

Define the term boiling point.

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Answer

The boiling point of a substance is the temperature at which its vapor pressure equals the atmospheric or external pressure. At this temperature, the substance transitions from a liquid to a gas.

Step 2

Give a reason why this is a fair comparison.

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Answer

The compounds Q, R, and S are all alkanes, which belong to the same molecular family, meaning they have similar molecular structures. This allows for a fair comparison of their boiling points since they will have comparable intermolecular forces and chain lengths.

Step 3

Which ONE of the three boiling points is most likely the boiling point of compound R? Explain the answer.

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Answer

The boiling point of compound R is most likely 55 °C. This is because compound R (3-methylpentane) is less branched than compound Q (2,2-dimethylbutane) and has similar surface area properties to compound S (Hexane). As a result, it exhibits stronger intermolecular forces compared to Q and weaker than S.

Step 4

Which compound (P or T) will be present in a greater amount in the SYRINGE? Explain the answer.

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Answer

Compound T (Pentan-1-ol) will be present in a greater amount in the syringe. Pentan-1-ol has stronger hydrogen bonding due to the presence of the hydroxyl group (-OH) compared to compound P (Pentanal), which primarily exhibits dipole-dipole interactions. This means that more energy is required to vaporize pentanal than pentan-1-ol.

Step 5

Explain the answer to QUESTION 3.4.1 by referring to the TYPES and STRENGTHS of intermolecular forces.

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Answer

In the mixture, Pentan-1-ol (compound T) has stronger hydrogen bonding compared to Pentanal (compound P), which possesses weaker dipole-dipole forces. Therefore, less energy is required to overcome the intermolecular forces of Pentan-1-ol, resulting in its greater presence in the vapor phase collected in the syringe.

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