3.1 Define the term melting point - NSC Physical Sciences - Question 3 - 2021 - Paper 2
Question 3
3.1 Define the term melting point.
3.2 Write down the general conclusion that can be made about the melting points of straight-chain alkanes.
3.3 Name the type of ... show full transcript
Worked Solution & Example Answer:3.1 Define the term melting point - NSC Physical Sciences - Question 3 - 2021 - Paper 2
Step 1
Define the term melting point.
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Answer
The melting point is defined as the temperature at which a solid becomes a liquid, indicating the point of equilibrium between the solid and liquid phases of a substance.
Step 2
Write down the general conclusion that can be made about the melting points of straight-chain alkanes.
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Answer
As the carbon chain length of straight-chain alkanes increases, the melting points tend to increase. This is due to the greater surface area and stronger Van der Waals forces that result from longer carbon chains.
Step 3
Name the type of Van der Waals forces between molecules of octane.
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Answer
The type of Van der Waals forces between molecules of octane is London dispersion forces.
Step 4
Write down the predominant phase of the following alkanes at -100 °C.
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Answer
3.4.1 Pentane: Solid
3.4.2 Octane: Solid
Step 5
Is the molecular mass of hexane GREATER THAN, LESS THAN or EQUAL to that of 2,2-dimethylbutane?
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Answer
The molecular mass of hexane is LESS THAN that of 2,2-dimethylbutane.
Step 6
Is the boiling point of 2,2-dimethylbutane HIGHER THAN or EQUAL TO that of hexane?
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Answer
The boiling point of 2,2-dimethylbutane is LOWER THAN that of hexane.
Step 7
Fully explain the answer to QUESTION 3.5.2.
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Answer
2,2-dimethylbutane is more branched compared to hexane, leading to a smaller surface area and weaker intermolecular forces. As a result, less energy is required to overcome these forces, resulting in a lower boiling point.