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Define the term unsaturated hydrocarbon - NSC Physical Sciences - Question 2 - 2023 - Paper 2

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Define the term unsaturated hydrocarbon. Write down the: 2.2.1 Letter that represents an UNSATURATED hydrocarbon 2.2.2 IUPAC name of compound A 2.2.3 IUPAC name ... show full transcript

Worked Solution & Example Answer:Define the term unsaturated hydrocarbon - NSC Physical Sciences - Question 2 - 2023 - Paper 2

Step 1

Define the term unsaturated hydrocarbon.

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Answer

An unsaturated hydrocarbon is a hydrocarbon that contains at least one carbon-carbon double bond (C=C) or triple bond (C≡C). This allows for the possibility of additional atoms, such as hydrogen, to bond with the carbon atoms, resulting in a structure that can undergo further reactions.

Step 2

Letter that represents an UNSATURATED hydrocarbon

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Answer

The letter that represents an unsaturated hydrocarbon is 'C'.

Step 3

IUPAC name of compound A

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Answer

The IUPAC name of compound A is 'butane'.

Step 4

IUPAC name of the POSITIONAL isomer of compound B

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Answer

The IUPAC name of the positional isomer of compound B is '2-methylpropane'.

Step 5

IUPAC name of compound D

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The IUPAC name of compound D is 'but-2-ene'.

Step 6

Balanced equation, using MOLECULAR FORMULA, for the complete combustion of compound A

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Answer

The balanced equation for the complete combustion of butane (C4H10) is:

ightarrow 8CO_2 + 10H_2O$$

Step 7

Define the term functional isomer.

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Functional isomers are compounds that have the same molecular formula but differ in the functional groups present. This results in different chemical properties despite having the same arrangement of atoms.

Step 8

Write down the STRUCTURAL FORMULA of each of these two FUNCTIONAL isomers

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For the functional isomers of C4H8O, the structural formulas are:

  1. For butanol (an alcohol): Butanol Structure

  2. For butan-2-one (a ketone): Butan-2-one Structure

Step 9

Determine the molecular formula of compound E by means of a calculation.

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Answer

To determine the molecular formula of compound E:

  1. Calculate the moles of carbon: moles_{C} = rac{mass}{molar ext{ }mass} = rac{1.09 ext{ g}}{12.01 ext{ g/mol}} = 0.0908 ext{ mol}

  2. Calculate the moles of hydrogen: moles_{H} = rac{0.18 ext{ g}}{1.008 ext{ g/mol}} = 0.1785 ext{ mol}

  3. Determine the ratio:

    • The simplest ratio is approximately 1:2.
  4. The empirical formula is C1H2.

  5. To find the molecular formula, compare the molar mass: extMolarmassofempiricalformula=112+21=14extg/mol ext{Molar mass of empirical formula} = 1*12 + 2*1 = 14 ext{ g/mol}

    • Compound E has a molar mass of 88 g/mol, which suggests that: rac{88 ext{ g/mol}}{14 ext{ g/mol}} ext{ approximately equals } 6.
    • Therefore, the molecular formula is C6H12.

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