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10.1 The four steps in the manufacture of an inorganic fertiliser are listed below - NSC Physical Sciences - Question 10 - 2019 - Paper 2

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10.1 The four steps in the manufacture of an inorganic fertiliser are listed below. These steps are NOT written in the order in which they occur. Step I: Sulphuric ... show full transcript

Worked Solution & Example Answer:10.1 The four steps in the manufacture of an inorganic fertiliser are listed below - NSC Physical Sciences - Question 10 - 2019 - Paper 2

Step 1

10.1.1 Correct order in which the steps occur in the preparation of the inorganic fertiliser by using the numbers I to IV

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Answer

The correct order of the steps in the preparation of the inorganic fertilizer is as follows:

II → IV → III → I

Step 2

10.1.2 Balanced chemical equation for step I

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Answer

The balanced chemical equation for step I is:

ightarrow (NH_4)_2SO_4$$

Step 3

10.1.3 NAME of the catalyst used in step II

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Answer

The catalyst used in step II is Vanadium pentoxide (V2O5).

Step 4

10.1.4 Balanced chemical equation for step IV

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Answer

The balanced chemical equation for step IV is:

ightarrow H_2S_2O_7$$

Step 5

10.1.5 Reason why sulphur trioxide is NOT dissolved in water in step IV

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Answer

Sulphur trioxide is not dissolved in water in step IV because the reaction is highly exothermic, which can produce corrosive mists and lead to hazardous conditions.

Step 6

10.2 Calculate the value of X

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Answer

To calculate the value of X, we can use the NPK ratio that typically follows the formula for fertilisers:

If the bag is labelled N-P-K (20-10-X) and the potassium mass is 3.33 kg, we can find the ratio as follows:

Given that:

  • N: 20%
  • P: 10%
  • K: X%

Letting the total mass of the fertiliser be 50 kg, we apply the ratio:

X=(3.33extkgK/50extkg)imes100X = (3.33 ext{ kg K} / 50 ext{ kg}) imes 100 Thus, we can deduce:

X=6.66X = 6.66 Therefore, the value of X is 6.66.

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