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'n Blok, met 'n massa van 8 kg, word op 'n ruwe horisontale oppervlak geplaas - NSC Physical Sciences - Question 2 - 2018 - Paper 1

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'n Blok, met 'n massa van 8 kg, word op 'n ruwe horisontale oppervlak geplaas. Die 8 kg-blok wat deur middel van 'n ligte, onbreekbare toutjie oor 'n ligte, wrywings... show full transcript

Worked Solution & Example Answer:'n Blok, met 'n massa van 8 kg, word op 'n ruwe horisontale oppervlak geplaas - NSC Physical Sciences - Question 2 - 2018 - Paper 1

Step 1

2.1 Stel Newton se Tweede Wet in woorde.

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Answer

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that when a net force acts on an object, it will accelerate in the direction of the force.

Step 2

2.2 Teken 'n benoemde vrye kragdiagram (vrye liggaamdiagram) vir die 8 kg-blok.

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Answer

The free body diagram for the 8 kg block will show the forces acting on it: the gravitational force acting downward (8 kg * 9.81 m/s²), the normal force acting upward, the tension in the rope acting at a 15° angle, and the frictional force opposing the movement.

Step 3

2.3 Wanneer die 8 kg-blok punt B bereik, is die hoek tussen die toutjie en die horisontaal 15° en die versnellings van die stelsel is 1,32 m·s²: 2.3.1 Gee 'n rede waarom die stelsel NIE in ewewig is NIE.

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Answer

The system is not in equilibrium because the net force acting on the 8 kg block is not zero. The force due to gravity and the tension force create a net force that causes acceleration.

Step 4

2.3.2 Gebruik die 2 kg-massa om die spanning in die toutjie te bereken.

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To find the tension T in the rope, we can use Newton's second law for the 2 kg mass:

Fnet=maF_{net} = ma

The net force is given by:

mgT=mamg - T = ma

Substituting the values:

T=mgmaT = mg - ma

Where m is 2 kg, g is 9.81 m/s², and a is 1.32 m/s²:

T=2imes9.812imes1.32T = 2 imes 9.81 - 2 imes 1.32

Thus, the tension can be calculated.

Step 5

2.3.3 Bereken die kinetiese wrywingskrag tussen die 8 kg-blok en die horisontale oppervlak.

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The kinetic frictional force can be calculated using:

fk=extmassimesextgravityimesextfrictioncoefficientf_k = ext{mass} imes ext{gravity} imes ext{friction coefficient}

Since the mass is 8 kg, gravity is 9.81 m/s², and the friction coefficient needs to be known, the equation can be set up, assuming an appropriate coefficient, to find the value of the kinetic friction.

Step 6

2.4 Soos die 8 kg-blok vanaf B na C beweeg, is die kinetiese wrywingskrag tussen die 8 kg-blok en die horisontale oppervlak nie konstant nie. Gee 'n rede vir hierdie stelling.

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Answer

The kinetic friction force is not constant as the normal force changes when the angle of the block increases. As the 8 kg block moves up the incline, the normal force decreases, resulting in a decrease in the frictional force.

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