Photo AI

Complete the following theorem: The line drawn from the centre of a circle to the midpoint of a chord is .. - NSC Technical Mathematics - Question 7 - 2019 - Paper 2

Question icon

Question 7

Complete-the-following-theorem:--The-line-drawn-from-the-centre-of-a-circle-to-the-midpoint-of-a-chord-is-..-NSC Technical Mathematics-Question 7-2019-Paper 2.png

Complete the following theorem: The line drawn from the centre of a circle to the midpoint of a chord is ... (1) In the diagram below, O is the centre of circle CA... show full transcript

Worked Solution & Example Answer:Complete the following theorem: The line drawn from the centre of a circle to the midpoint of a chord is .. - NSC Technical Mathematics - Question 7 - 2019 - Paper 2

Step 1

Determine, with reasons, the size of angle CĂI

96%

114 rated

Answer

Since angle CĂI and angle DBE lie in the same segment, we can conclude that:

CA˘I=DBE=26.6°CĂI = DBE = 26.6°

Thus, the size of angle CĂI is 26.6°.

Step 2

Determine, with reasons, the size of angle AĂ

99%

104 rated

Answer

To find angle AĂ, we use the property that the sum of the angles in a triangle equals 180°:

AA˘+CA˘I+AEB=180°AĂ + CĂI + AEB = 180° Substituting the known values: AA˘+26.6°+90°=180°AĂ + 26.6° + 90° = 180° Solving for AĂ gives: AA˘=180°26.6°90°=63.4°AĂ = 180° - 26.6° - 90° = 63.4°

Step 3

Determine, with reasons, the size of angle BĮ

96%

101 rated

Answer

Since angle BĮ lies in a semicircle, we have:

BĮ=90°26.6°=63.4°BĮ = 90° - 26.6° = 63.4°

Therefore, angle BĮ is also 63.4°.

Step 4

Write down, without giving reasons, the length of AE

98%

120 rated

Answer

The length of AE is given as:

AE=4extunitsAE = 4 ext{ units}

Step 5

Write down, without giving reasons, the length of ED in terms of x

97%

117 rated

Answer

The length of ED can be expressed as:

ED=5xextunitsED = 5 - x ext{ units}

Step 6

Hence, or otherwise, determine the numerical value of x

97%

121 rated

Answer

To find the numerical value of x, we can use the Pythagorean theorem in triangle AOE:

Using the relationship: AO2=AE2+OE2AO^2 = AE^2 + OE^2 Substituting values: 82=42+x28^2 = 4^2 + x^2 64=16+x264 = 16 + x^2 Solving: x2=6416=48x^2 = 64 - 16 = 48 x=ext48=4ext3extorx=3x = ext{√}48 = 4 ext{√}3 ext{ or } x = 3. Thus, the numerical value of x is 3.

Join the NSC students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;