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10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden - NSC Technical Mathematics - Question 10 - 2021 - Paper 2

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10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden. The diagram below shows the circular areas c... show full transcript

Worked Solution & Example Answer:10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden - NSC Technical Mathematics - Question 10 - 2021 - Paper 2

Step 1

The length of BC

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Answer

To find the length of BC, we need to determine the height of the segment created by the bottom sprinkler.

First, we can calculate the height using the formula:

BC=OCOBBC = OC - OB

Substituting the given values:

BC=6.95extm4.00extm=2.95extmBC = 6.95 ext{ m} - 4.00 ext{ m} = 2.95 ext{ m}

Thus, the length of BC is 2.95 m.

Step 2

The length of chord ED

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Answer

To determine the length of chord ED, we will apply the Pythagorean theorem. The distance from O to the point where the tangent (chord EBD) meets the smaller circle is denoted as h, and the radius of the smaller circle is r = 4 m.

We first need to determine the height of the segment, which we calculated as:

h=2.95extmh = 2.95 ext{ m}

Using the formula for the half-chord:

rac{ED}{2} = ext{sqrt}(r^2 - h^2)

In our case:

=4extmextandh=2.95extm ED=2imesextsqrt(422.952) = 4 ext{ m} ext{ and } h = 2.95 ext{ m}\ ED = 2 imes ext{sqrt}(4^2 - 2.95^2)

Calculating this, we find:

Thus, the length of chord ED is 5.40 m.

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