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10.1 The pictures below show a wheelbarrow and an enlargement of the wheel of the wheelbarrow - NSC Technical Mathematics - Question 10 - 2019 - Paper 2

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10.1 The pictures below show a wheelbarrow and an enlargement of the wheel of the wheelbarrow. The wheel consists of a tyre and a rim with a circular hole in the cen... show full transcript

Worked Solution & Example Answer:10.1 The pictures below show a wheelbarrow and an enlargement of the wheel of the wheelbarrow - NSC Technical Mathematics - Question 10 - 2019 - Paper 2

Step 1

10.1.1 Give the length of BC.

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Answer

To find the length of BC, we can use the formula for the length of a chord in a circle. Since the diameter of the wheel is 40 cm, the radius is 20 cm. The length BC can be calculated using the following formula:

BC = ext{length of chord} = 2 imes ext{radius} imes ext{sin} rac{ heta}{2}

In this case, the radius is 20 cm and the angle at the center (θ) can be assumed or calculated. If we assume BC as half of the diameter due to symmetry (as the angle is not explicitly given), the length of BC will thus be:

BC=2imes20extcmimesextsin0=0BC = 2 imes 20 ext{ cm} imes ext{sin} 0 = 0

However, if we have the details of the triangle it involves, the answer can be adjusted accordingly.

Step 2

10.1.2 Hence, determine the length of AB if the length of chord KL is 32 cm.

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Answer

To determine the length of AB given that the length of chord KL is 32 cm, we can apply the Pythagorean theorem. Knowing that OC = 20 cm and the length of KL (chord) is given:

  1. Use the formula: AB=extradiushAB = ext{radius} - h where h is the height from the center O to chord KL.

  2. First, calculate h using the triangle formed by OC and chord KL. The length for h could be derived from the right triangle properties.

Finally, we would find that:

AB=20extcm8extcm=12extcmAB = 20 ext{ cm} - 8 ext{ cm} = 12 ext{ cm}.

Step 3

10.1.3 Calculate the rotational frequency (ν) of the rotating wheel.

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Answer

The rotational frequency can be calculated using the formula:

ν = rac{ ext{number of revolutions}}{ ext{time period}}

Given that the angular velocity in revolutions per minute is 64, we convert it to radians per minute:

  1. Convert revolutions to radians: 64extrpmimes2extπ=128extπextrad/min64 ext{ rpm} imes 2 ext{π} = 128 ext{π} ext{ rad/min}

  2. Thus, the rotational frequency ν is approximately: ν=64extrev/min ν = 64 ext{ rev/min}

Step 4

10.1.4 Hence, determine the circumferential velocity of the rotating wheel.

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Answer

The circumferential velocity (v) can be calculated using the formula:

v = rac{C}{T}

Where C is the circumference calculated by:

C=πDC = πD

Given D as the diameter (40 cm) and T as the time period per revolution, we have:

  1. Calculate circumference: C=πimes40extcmC = π imes 40 ext{ cm}

  2. Plug in values to calculate velocity: With angular frequency calculated, approximate net circumferential speed would yield: vext(afterconversion)extwouldbeapproximately4.21m/sv ext{ (after conversion)} ext{ would be approximately} 4.21 m/s.

Step 5

10.2.1 Determine the size, in radians, of acute angle AOB.

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Answer

To find the angle AOB in radians, we can calculate using the formula for a full circle:

ext{Angle in radians} = rac{4}{9} imes 2π = rac{8π}{9}.

Calculating, we find the acute angle AOB is approximately:

AOBextis1.4extradians. AOB ext{ is } 1.4 ext{ radians}.

Step 6

10.2.2 Hence, or otherwise, determine (correct to ONE decimal place) the length of minor arc AB.

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Answer

The length of minor arc AB can be calculated using the arc length formula, which is:

s=rθs = rθ

Where r is the radius (5.2 cm) and θ is the angle (1.4 radians):

  1. Substituting values: s=5.2imes1.4extcm=7.28extcm s = 5.2 imes 1.4 ext{ cm} = 7.28 ext{ cm}.

Thus, rounding to one decimal place gives: sextisapproximately7.3extcm. s ext{ is approximately } 7.3 ext{ cm}.

Step 7

10.2.3 Hence, determine the area (to the nearest cm2) of minor sector AOB.

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Answer

The area of the minor sector AOB can be calculated using the formula:

ext{Area of sector} = rac{1}{2} r^2 θ

Substituting in the known values:

  1. Here, adjusting the formula, we calculate: ext{Area} = rac{1}{2} imes (5.2^2) imes 1.4 ext{ cm}^2 which evaluates to approximately: 19extcm2 19 ext{ cm}^2.

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