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10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden - NSC Technical Mathematics - Question 10 - 2021 - Paper 2

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10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden. The diagram below shows the circular areas c... show full transcript

Worked Solution & Example Answer:10.1 A double-headed rotating sprinkler (as shown in the picture below) is used to irrigate a circular vegetable garden - NSC Technical Mathematics - Question 10 - 2021 - Paper 2

Step 1

(a) The length of BC

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Answer

To find the length of BC, we can use the distance from point O to point B, which is the radius of the smaller circle, and subtract it from the radius of the larger circle:

  1. Identify the radius of the larger circle: 6.95 m

  2. Identify the radius of the smaller circle: 4 m

  3. Calculate the length of BC:

    BC=OCOB=6.954=2.95extmBC = OC - OB = 6.95 - 4 = 2.95 ext{ m}

Thus, the length of BC is 2.95 m.

Step 2

(b) The length of chord ED

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Answer

To calculate the length of chord ED, we can apply the Pythagorean theorem:

  1. Identify the radius of the smaller circle (OB): 4 m

  2. Determine the height of segment (h):

    h=2.95extmh = 2.95 ext{ m}

  3. Using the formula for the half chord, we start with:

    x2+h2=r2x^2 + h^2 = r^2

    where:

    • r is the radius of the smaller circle (4 m)
    • x is half the length of the chord ED.

    Substitute:

    x2+(2.95)2=(4)2x^2 + (2.95)^2 = (4)^2

    x2+8.7025=16x^2 + 8.7025 = 16

    x2=168.7025x^2 = 16 - 8.7025

    x2=7.2975x^2 = 7.2975

    x=extsqrt(7.2975)extm extandthus,xextapproximately2.70extmx = ext{sqrt}(7.2975) ext{ m} \ ext{ and thus, } x ext{ approximately } 2.70 ext{ m}

  4. The length of chord ED is:

    ED=2x=2(2.70)=5.40extmED = 2x = 2(2.70) = 5.40 ext{ m}

Thus, the length of chord ED is 5.40 m.

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