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The graphs below represent the curves of functions $f$ and $g$ defined by $f(x) = a \, \sin x$ and $g(x) = - \cos b x$ respectively for $x \in [0 ; 180^\circ]$ - NSC Technical Mathematics - Question 5 - 2019 - Paper 2

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The-graphs-below-represent-the-curves-of-functions-$f$-and-$g$-defined-by---$f(x)-=-a-\,-\sin-x$-and-$g(x)-=---\cos-b-x$-respectively-for-$x-\in-[0-;-180^\circ]$-NSC Technical Mathematics-Question 5-2019-Paper 2.png

The graphs below represent the curves of functions $f$ and $g$ defined by $f(x) = a \, \sin x$ and $g(x) = - \cos b x$ respectively for $x \in [0 ; 180^\circ]$. ... show full transcript

Worked Solution & Example Answer:The graphs below represent the curves of functions $f$ and $g$ defined by $f(x) = a \, \sin x$ and $g(x) = - \cos b x$ respectively for $x \in [0 ; 180^\circ]$ - NSC Technical Mathematics - Question 5 - 2019 - Paper 2

Step 1

Give the period of $f$

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Answer

The period of the sine function f(x)=asinxf(x) = a \sin x is 360360^\circ. Therefore, the period of ff is 360.

Step 2

Determine the numerical values of $a$ and $b$

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Answer

From the graph, it can be observed that the maximum value of f(x)f(x) is 2, which suggests that a=2a = -2. Also, the maximum value of g(x)g(x) is at 1, which suggests that b=2b = 2.

Step 3

Write down the coordinates of $T$

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Answer

The coordinates of point TT can be determined from the graph as follows:
T(158.5;0.7)T(158.5^\circ; -0.7).

Step 4

Determine the value(s) of $x$ for which: g(x) \cdot f(x) > 0$ for $x \in [90^\circ ; 180^\circ]$

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Answer

The product g(x)f(x)>0g(x) \cdot f(x) > 0 holds true when both functions are either both positive or both negative. Analyzing the graph, this occurs for:
135<x<180135^\circ < x < 180^\circ.
Thus, x[135;180]x \in [135^\circ ; 180^\circ].

Step 5

Determine the value(s) of $x$ for which: $f(x)$ will be undefined

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Answer

The function f(x)f(x) will be undefined specifically whenever the sine function oscillates. However, from the equation provided, we look for other points. Hence, x=45x = 45^\circ or x=135x = 135^\circ.

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