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An electric kettle with resistance 22 Ω and a microwave oven with resistance 44 Ω are connected in parallel and the combination is connected across a source of voltage 230 V as shown in the diagram - NSC Technical Sciences - Question 9 - 2022 - Paper 1

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Question 9

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An electric kettle with resistance 22 Ω and a microwave oven with resistance 44 Ω are connected in parallel and the combination is connected across a source of volta... show full transcript

Worked Solution & Example Answer:An electric kettle with resistance 22 Ω and a microwave oven with resistance 44 Ω are connected in parallel and the combination is connected across a source of voltage 230 V as shown in the diagram - NSC Technical Sciences - Question 9 - 2022 - Paper 1

Step 1

9.1 Total resistance of the circuit

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Answer

To find the total resistance ( R_T) of resistors in parallel, we use the formula:

1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}

Substituting the values gives us:

1RT=122+144\frac{1}{R_T} = \frac{1}{22} + \frac{1}{44}

Finding a common denominator (44):

1RT=244+144=344\frac{1}{R_T} = \frac{2}{44} + \frac{1}{44} = \frac{3}{44}

Therefore:

RT=44314.67ΩR_T = \frac{44}{3} \approx 14.67 \Omega

Step 2

9.2 Power dissipated by the electric kettle

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Answer

The power ( P) in an electrical circuit is calculated using the formula:

P=V2RP = \frac{V^2}{R}

where V is the voltage and R is the resistance.

For the electric kettle, substituting the values:

P=230222=52900222404.55WP = \frac{230^2}{22} = \frac{52900}{22} \approx 2404.55 W

Step 3

9.3 Heat produced in the electric kettle in 2 minutes

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Answer

The heat produced ( W) can be calculated with the formula:

W=PtW = P \cdot t

where P is the power and t is the time in seconds.

For 2 minutes:

t=2×60=120 secondst = 2 \times 60 = 120 \text{ seconds}

Substituting the values:

W=2404.55120288546Ws=288546JW = 2404.55 \cdot 120 \approx 288546 W \cdot s = 288546 J

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