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The cell notation below represents an electrochemical cell: Cu/Cu²⁺ (1 mol·dm⁻³) // Ag⁺ (1 mol·dm⁻³) / Ag 298 K/25 °C 6.1.1 What energy conversion is taking place in the above cell? 6.1.2 Write down TWO indicators from the cell notation that prove that the cell is operating under standard conditions - NSC Technical Sciences - Question 6 - 2022 - Paper 2

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The-cell-notation-below-represents-an-electrochemical-cell:-Cu/Cu²⁺-(1-mol·dm⁻³)-//-Ag⁺-(1-mol·dm⁻³)-/-Ag-298-K/25-°C--6.1.1-What-energy-conversion-is-taking-place-in-the-above-cell?--6.1.2-Write-down-TWO-indicators-from-the-cell-notation-that-prove-that-the-cell-is-operating-under-standard-conditions-NSC Technical Sciences-Question 6-2022-Paper 2.png

The cell notation below represents an electrochemical cell: Cu/Cu²⁺ (1 mol·dm⁻³) // Ag⁺ (1 mol·dm⁻³) / Ag 298 K/25 °C 6.1.1 What energy conversion is taking place i... show full transcript

Worked Solution & Example Answer:The cell notation below represents an electrochemical cell: Cu/Cu²⁺ (1 mol·dm⁻³) // Ag⁺ (1 mol·dm⁻³) / Ag 298 K/25 °C 6.1.1 What energy conversion is taking place in the above cell? 6.1.2 Write down TWO indicators from the cell notation that prove that the cell is operating under standard conditions - NSC Technical Sciences - Question 6 - 2022 - Paper 2

Step 1

6.1.1 What energy conversion is taking place in the above cell?

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Answer

The energy conversion occurring in the electrochemical cell is from chemical energy to electrical energy. This process is a hallmark of electrochemical reactions, wherein the oxidation and reduction reactions generate an electric current.

Step 2

6.1.2 Write down TWO indicators from the cell notation that prove that the cell is operating under standard conditions.

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Answer

  1. The concentration of the electrolyte is specified as 1 mol·dm⁻³, which indicates standard concentration.
  2. The temperature is provided as 298 K, representing standard temperature conditions.

Step 3

6.2.1 Cathode

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Answer

The balanced half-reaction at the cathode is:

ightarrow ext{Ag}(s)$$

Step 4

6.2.2 Anode

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The balanced half-reaction at the anode is:

ightarrow ext{Cu}^{2+}(aq) + 2e^-$$

Step 5

6.3 Use calculations to conclude whether the reaction is SPONTANEOUS or NON-SPONTANEOUS.

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Answer

To determine if the reaction is spontaneous, we can calculate the cell potential (E°cell) using:

E°cell=E°cathodeE°anodeE°_{cell} = E°_{cathode} - E°_{anode}

Using the provided values:

  • For the cathode (Ag): E° = +0.80 V
  • For the anode (Cu): E° = +0.34 V

Now substituting the values:

E°cell=0.80V0.34V=0.46VE°_{cell} = 0.80 V - 0.34 V = 0.46 V

Since E°cell is positive, the reaction is spontaneous.

Step 6

6.4 Give a reason for the answer to QUESTION 6.3.

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Answer

The reaction is spontaneous because the standard cell potential (E°cell) is positive, indicating that the electrochemical process can occur naturally without external energy input.

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