7.1 Identify the type of electromagnetic radiation that is used in the diagram above - NSC Technical Sciences - Question 7 - 2023 - Paper 1

Gamma rays have the highest penetrating ability, allowing them to effectively target and kill cancer cells.

We can calculate the energy of a photon using the formula:

$E = \frac{hc}{\lambda}$

Where:

• $h = 6.63 \times 10^{-34} \text{ J s}$ (Planck's constant)
• $c = 3 \times 10^{8} \text{ m/s}$ (speed of light)
• $\lambda = 5 \times 10^{-12} \text{ m}$ (wavelength)

Substituting the values: $E = \frac{(6.63 \times 10^{-34}) (3 \times 10^{8})}{5 \times 10^{-12}} \approx 3.978 \times 10^{-14} \text{ J}$

Lens 1 is a convex lens, and Lens 2 is also a convex lens.

The type of image formed at point B is VIRTUAL.

The image at point B is virtual because it is formed where the rays of light appear to converge when extended. In this case, the observer sees the image as if it is located behind the lens.

One other practical application of convex lenses is in cameras.