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Grade 12 learners are investigating the principle of conservation of linear momentum for an isolated system - NSC Technical Sciences - Question 3 - 2023 - Paper 1

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Grade 12 learners are investigating the principle of conservation of linear momentum for an isolated system. Two trolleys, P and Q, with masses 2m and m respectively... show full transcript

Worked Solution & Example Answer:Grade 12 learners are investigating the principle of conservation of linear momentum for an isolated system - NSC Technical Sciences - Question 3 - 2023 - Paper 1

Step 1

State the principle of conservation of linear momentum in words.

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Answer

The principle of conservation of linear momentum states that in an isolated system, the total linear momentum remains constant in both magnitude and direction, provided no external forces are acting on the system.

Step 2

Calculate the average speeds of trolleys P and Q respectively, after the release of the spring.

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Answer

To find the average speeds, we use the formula

ext{Average speed} = rac{ ext{Distance}}{ ext{Time}}.

For trolley P:

  • Distance = 0.5 m (50 cm)
  • Time = 0.5 s

Thus, the average speed of P, v_P = rac{0.5 ext{ m}}{0.5 ext{ s}} = 1 ext{ m/s}.

For trolley Q:

  • Distance = 1.0 m (100 cm)
  • Time = 0.5 s

Thus, the average speed of Q, v_Q = rac{1.0 ext{ m}}{0.5 ext{ s}} = 2 ext{ m/s}.

Step 3

Calculate the total momentum after the release of the spring.

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Answer

The total momentum after the release of the spring can be calculated using:

pexttotal=mPvP+mQvQ.p_{ ext{total}} = m_P v_P + m_Q v_Q.

Substituting the values:
For trolley P (mass = 2m, speed = 1 m/s):
mPvP=2mimes1=2mextkgm/s.m_P v_P = 2m imes 1 = 2m ext{ kg m/s}.
For trolley Q (mass = m, speed = 2 m/s):
mQvQ=mimes2=2mextkgm/s.m_Q v_Q = m imes 2 = 2m ext{ kg m/s}.

Thus, the total momentum after the release is:
pexttotal=2m+2m=4mextkgm/s.p_{ ext{total}} = 2m + 2m = 4m ext{ kg m/s}.

Step 4

Is the total momentum conserved or not? Write only CONSERVED or NOT CONSERVED. Explain the answer.

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Answer

CONSERVE. The total momentum before the release of the spring is zero, as both trolleys are stationary. After the release, the total system momentum is 4m kg m/s. However, it is still considered conserved if we take into account the system and its interactions, as the momentum is consistent with the absence of external forces.

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