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VRAAG 10 (Begin op 'n nuwe bladsy.) 10.1 Bestudeer die diagram van die GS-motor hieronder getoon - NSC Technical Sciences - Question 10 - 2022 - Paper 1

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VRAAG 10 (Begin op 'n nuwe bladsy.) 10.1 Bestudeer die diagram van die GS-motor hieronder getoon. Beantwoord die vrae wat volg. 10.1.1 Definieer 'n elektriese moto... show full transcript

Worked Solution & Example Answer:VRAAG 10 (Begin op 'n nuwe bladsy.) 10.1 Bestudeer die diagram van die GS-motor hieronder getoon - NSC Technical Sciences - Question 10 - 2022 - Paper 1

Step 1

Definieer 'n elektriese motor.

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Answer

An electric motor is a device that converts electrical energy to mechanical energy. It operates by using the interactions between magnetic fields and current-carrying conductors to produce rotational motion.

Step 2

Noem Een eienskap wat dit 'n GS-motor maak.

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Answer

A distinguishing feature of a GS motor is its commutator, which allows for the reversal of current direction in the motor windings, enabling continuous rotation.

Step 3

Noem die spoel KLOKSWYS OF ANTI-KLOKSWYS sal roteer. Neem aan dat die spoel punt O waarneem word.

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Answer

The coil will rotate anti-clockwise when viewed from point O, assuming the current direction and magnetic field are appropriately aligned.

Step 4

Noem die energiegebruik wat in 'n WS-generator plaasvind.

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Answer

In a WS-generator, mechanical energy is converted into electrical energy through electromagnetic induction.

Step 5

'n Transformator het 1 500 sekondêre windings en 250 primêre windings. Indien die sekondêre potensiaalverskil (spanning) 240 V is, bereken die primêre potensiaalverskil (spanning).

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Answer

Using the transformer equation, VsVp=NsNp\frac{V_s}{V_p} = \frac{N_s}{N_p} where

  • VsV_s = secondary voltage = 240 V,
  • NsN_s = number of secondary windings = 1500,
  • NpN_p = number of primary windings = 250, we can rearrange to find VpV_p:

Vp=VsNpNs=2402501500=40 V.V_p = V_s \cdot \frac{N_p}{N_s} = 240 \cdot \frac{250}{1500} = 40 \text{ V}. Therefore, the primary potential difference is 40 V.

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