A total magnetic flux of 9 Wb passes through a rectangular coil with a length of 150 mm and a width of 90 mm - NSC Technical Sciences - Question 9 - 2021 - Paper 1

To calculate the magnetic flux density (B), we use the formula:

$B = \frac{\Phi}{A}$

Where:

• ( \Phi ) is the magnetic flux (in Webers) = 9 Wb
• ( A ) is the area of the coil.

First, convert the dimensions from mm to meters:

• Length = 150 mm = 0.150 m
• Width = 90 mm = 0.090 m

Now, calculate the area:

$A = L \times W = 0.150 \text{ m} \times 0.090 \text{ m} = 0.0135 \text{ m}^2$

Next, substitute the values into the flux density formula:

$B = \frac{9 \text{ Wb}}{0.0135 \text{ m}^2} \approx 666.67 \text{ T}$

Thus, the magnetic flux density that passes through the rectangular coil is approximately 666.67 T.