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4.1 'n Gereedskapskissie met 'n massa van 40 kg word deur 'n toegepaste krag van 60 N oor 'n afstand van 8 m getrek - English General - NSC Technical Sciences - Question 4 - 2021 - Paper 1

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4.1---'n-Gereedskapskissie-met-'n-massa-van-40-kg-word-deur-'n-toegepaste-krag-van-60-N-oor-'n-afstand-van-8-m-getrek-English General-NSC Technical Sciences-Question 4-2021-Paper 1.png

4.1 'n Gereedskapskissie met 'n massa van 40 kg word deur 'n toegepaste krag van 60 N oor 'n afstand van 8 m getrek. Die toegepaste krag maak 'n hoek van 25° met d... show full transcript

Worked Solution & Example Answer:4.1 'n Gereedskapskissie met 'n massa van 40 kg word deur 'n toegepaste krag van 60 N oor 'n afstand van 8 m getrek - English General - NSC Technical Sciences - Question 4 - 2021 - Paper 1

Step 1

Definieer arbeid verrig.

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Answer

Arbeid verrig is die produk van die krag wat op 'n voorwerp uitgeoefen word en die verplasing in die rigting van die krag. Dit kan gemathematies uitgedruk word as: W=Fimesdimesextcos(heta)W = F imes d imes ext{cos}( heta) waar WW die arbeid, FF die toegepaste krag, dd die verplasing, en heta heta die hoek tussen die krag en die verplasing is.

Step 2

Bereken die arbeid deur die toegepaste krag oor die 8 m verrig.

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Answer

Om die arbeid te bereken, kan ons die formule gebruik: W=Fimesdimesextcos(heta)W = F imes d imes ext{cos}( heta) HierBy is F=60extNF = 60 ext{ N}, d=8extmd = 8 ext{ m}, en heta=25exto heta = 25^ ext{o}.

Berekening:

W ext{ (arbeid)} = 435.03 ext{ J} $$

Step 3

Stel die beginsel van die behoud van mekaniese energie in woorde.

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Answer

Die beginsel van die behoud van mekaniese energie stel dat die totale meganiese energie van 'n geisoleerde stelsel konstant bly, mits daar geen eksterne kragte of werking op die stelsel inwerk nie. Dit beteken dat die som van die kinetiese en potensiële energie in 'n geisoleerde stelsel nie sal verander nie.

Step 4

Bereken die potensiële energie wat deur die konstruksiewerker verkry is 12 m bokant die aarde se oppervlak.

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Answer

Die potensiële energie (EpE_p) kan bereken word met die formule: Ep=mghE_p = mgh waar:

  • m=75extkgm = 75 ext{ kg} (massa van die werker)
  • g=9.8extm/s2g = 9.8 ext{ m/s}^2 (versnelling van die gravitatie)
  • h=12extmh = 12 ext{ m} (hoogte)

Berekening:

E_p = 8820 ext{ J} $$

Step 5

Die totale mekaniese energie van die konstruksiewerker by die hoogste punt is 11 500 J. Bepaal die kinetiese energie van die konstruksiewerker op daardie punt.

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Answer

Die totale meganiese energie (EtotE_{tot}) is die som van die potensiële energie (EpE_p) en die kinetiese energie (EkE_k).

Etot=Ep+EkE_{tot} = E_p + E_k

Daarom kan ons die kinetiese energie bereken:

E_k = 11500 - 8820 \\ E_k = 2680 ext{ J} $$

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