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The cell notation of a standard galvanic (voltaic) cell containing an unknown metal Y is shown below - English General - NSC Technical Sciences - Question 6 - 2022 - Paper 2

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The cell notation of a standard galvanic (voltaic) cell containing an unknown metal Y is shown below. Y (s) | Y2+ (aq) || Cu2+ (aq) | Cu (s) 6.1 What do the single... show full transcript

Worked Solution & Example Answer:The cell notation of a standard galvanic (voltaic) cell containing an unknown metal Y is shown below - English General - NSC Technical Sciences - Question 6 - 2022 - Paper 2

Step 1

What do the single vertical lines (|) in the cell notation represent?

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Answer

The single vertical lines (|) in the cell notation represent the phase boundaries or interfaces between the different states of matter in the galvanic cell. They indicate the separation between the solid and aqueous phases.

Step 2

State TWO standard conditions for the cell.

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  1. The concentration of ions involved in the reactions must be 1 mol/dm³.
  2. The temperature at which the cell operates must be 25 °C (298 K).

Step 3

Write down the NAME or FORMULA of the oxidising agent.

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The oxidising agent in this galvanic cell is Copper(II) ions, represented as Cu²+.

Step 4

Identify the polarity of the:

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Answer

6.4.1 Anode: Negative 6.4.2 Cathode: Positive

Step 5

The initial reading on a voltmeter connected across the electrodes is 1.10 V. Use a calculation to identify metal Y.

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Answer

To identify metal Y, we can use the standard cell potential equation:

Ecell=EcathodeEanodeE_{cell} = E_{cathode} - E_{anode}

Given the cell potential ( 1.10 V), we can assume:

  • For Cu, Ecathode=+0.34extVE_{cathode} = +0.34 ext{ V} (standard reduction potential). We need to find EanodeE_{anode} for metal Y.

Rearranging gives us:

Eanode=EcathodeEcellE_{anode} = E_{cathode} - E_{cell}

Plugging in the values:

Eanode=0.34extV1.10extV=0.76extVE_{anode} = 0.34 ext{ V} - 1.10 ext{ V} = -0.76 ext{ V}

Using standard reduction potentials, if Y is Zinc (Zn), then EZn=0.76extVE_{Zn} = -0.76 ext{ V}. Therefore, metal Y is Zinc (Zn).

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