The Mole and Conversions (HSC SSCE Chemistry): Flashcards

$6.022 imes 10^{23}$ particles per mole

Quantity with as many units as in exactly 12 g of C-12

Mass of one mole of a substance (g/mol)

$n = \frac{m}{MM}$

$N = n \times N_A$

As number of particles ($6.022 \times 10^{23}$) or as mass (g)

32 g/mol vs 16 g/mol

g mol⁻¹ or g/mol

Mass → moles (÷MM) → particles (×$N_A$)

mol