See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
10 questions from this quiz
Extent of weak base splitting in water
Kb=[BH+][OH−][B]K_b = \frac{[\text{BH}^+][\text{OH}^-]}{[\text{B}]}Kb=[B][BH+][OH−]
Larger KbK_bKb indicates a stronger base
Nearly 100%
[OH−]=[NH4+][\text{OH}^-] = [\text{NH}_4^+][OH−]=[NH4+]
Ka×Kb=KwK_a \times K_b = K_wKa×Kb=Kw
[OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}[OH−]=10−pOH
Equilibrium [B]≈[\text{B}] \approx[B]≈ initial [B][\text{B}][B]
Phosphate ion (Kb=5.9×10−3K_b = 5.9 \times 10^{-3}Kb=5.9×10−3)
1.8×10−51.8 \times 10^{-5}1.8×10−5
Select your subjects, and get access to A+ resources today.