The Mole and Conversions (HSC SSCE Chemistry): Quizzes

$6.022 \times 10^{23}$ particles per mole

12 g

$6.022 \times 10^{23}$ atoms of silver

g mol$^{-1}$

32 g

$n = \frac{m}{MM}$

$N = n \times N_A$

Mass → Moles → Particles (two steps)

71 g

mol