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10 questions from this quiz
Moles of solute per litre of solution
c=nVc = \frac{n}{V}c=Vn
mol L−1\text{mol L}^{-1}mol L−1
n=cVn = cVn=cV
Converts millilitres to litres
Solution with accurately known conc.
0.60 mol L−10.60 \text{ mol L}^{-1}0.60 mol L−1
n=mMMn = \frac{m}{MM}n=MMm
Molarity increases
0.00250.00250.0025 mol
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