Molarity (HSC SSCE Chemistry): Quizzes

Moles of solute per litre of solution

$c = \frac{n}{V}$

$\text{mol L}^{-1}$

$n = cV$

Converts millilitres to litres

Solution with accurately known conc.

$0.60 \text{ mol L}^{-1}$

$n = \frac{m}{MM}$

Molarity increases

$0.0025$ mol