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10 questions from this quiz
Etotal=Ered+EoxidE_{\text{total}} = E_{\text{red}} + E_{\text{oxid}}Etotal=Ered+Eoxid
Reverse the sign of the reduction potential
The potential value stays the same
The reaction is spontaneous as written
The reverse reaction is spontaneous
The one with higher electrode potential
Ecell=εA−εBE_{\text{cell}} = \varepsilon_A - \varepsilon_BEcell=εA−εB
1.62 V positive
Cu, Cu²⁺ electrode
Non-standard conditions
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