Further Applications of Differentiation (HSC SSCE Mathematics Advanced): Flashcards

$\frac{1}{x}$

$x > 0$

$-\frac{1}{m}$ (negative reciprocal)

$\log_e x + 1$

$\frac{1}{x}$

$x = 1$

$0$

$0$

$x$ grows/shrinks faster than $\log_e x$

Minimum