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10 questions from this quiz
Probability of A given B has occurred
It reduces to just outcomes within B
P(A∣B)=∣A∩B∣∣B∣P(A|B) = \frac{|A \cap B|}{|B|}P(A∣B)=∣B∣∣A∩B∣
Number of outcomes in both A and B
When you have probabilities not counts
35\frac{3}{5}53
0.1350.1350.135
Tree diagrams
111
P(B)≠0P(B) \neq 0P(B)=0
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