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10 questions from this quiz
Events that cannot happen at the same time
∅\emptyset∅ (empty set)
Separate circles that do not overlap
Yes, a card cannot be both suits
P(A‾)=1−P(A)P(\overline{A}) = 1 - P(A)P(A)=1−P(A)
P(A)+P(B)−P(A∩B)P(A) + P(B) - P(A \cap B)P(A)+P(B)−P(A∩B)
P(A)+P(B)P(A) + P(B)P(A)+P(B)
To avoid double-counting overlapping outcomes
23\frac{2}{3}32
No, they share outcome 6
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