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10 questions from this quiz
tan=OppositeAdjacent\tan = \frac{\text{Opposite}}{\text{Adjacent}}tan=AdjacentOpposite
22\frac{\sqrt{2}}{2}22
12\frac{1}{2}21
13\frac{1}{\sqrt{3}}31
1:1:21 : 1 : \sqrt{2}1:1:2
1:3:21 : \sqrt{3} : 21:3:2
sinθ=cos(90°−θ)\sin \theta = \cos(90° - \theta)sinθ=cos(90°−θ)
60°60°60°
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