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10 cards from this deck
Experiment with 2+ events happening in sequence
Complete set of all possible outcomes
Down the leftmost column
Across the top row
Combine row outcome with column outcome
Right-hand side where branches end
Count all the endpoints
First item returned before selecting second
P(event)=n(event)n(S)P(\text{event}) = \frac{n(\text{event})}{n(S)}P(event)=n(S)n(event)
Both give the same sample space
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