Applications of the Uniform Circular Motion Model (HSC SSCE Physics): Flashcards

Gravitational force ($mg$) and tension force ($F_T$)

Only tension (pulling force) along its length

$F_T \cos\theta = \frac{mv^2}{r}$

$F_T \sin\theta = -mg$

$F_T = \frac{mv^2}{r} + mg$

Friction force on the tyres

Increases with square of velocity ($v^2$)

Water, oil, mud, worn tyres, smooth surfaces

$mg \tan\theta = \frac{mv^2}{r}$

No, it's independent of vehicle mass