See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
10 cards from this deck
Gravitational force (mgmgmg) and tension force (FTF_TFT)
Only tension (pulling force) along its length
FTcosθ=mv2rF_T \cos\theta = \frac{mv^2}{r}FTcosθ=rmv2
FTsinθ=−mgF_T \sin\theta = -mgFTsinθ=−mg
FT=mv2r+mgF_T = \frac{mv^2}{r} + mgFT=rmv2+mg
Friction force on the tyres
Increases with square of velocity (v2v^2v2)
Water, oil, mud, worn tyres, smooth surfaces
mgtanθ=mv2rmg \tan\theta = \frac{mv^2}{r}mgtanθ=rmv2
No, it's independent of vehicle mass
Select your subjects, and get access to A+ resources today.