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10 cards from this deck
a⃗=F⃗netm\vec{a} = \frac{\vec{F}_{\text{net}}}{m}a=mFnet
Acceleration increases
Acceleration decreases
Constant acceleration
Vector quantities (magnitude and direction)
Same direction
Apply Newton's 2nd law to find acceleration
v=u+atv = u + atv=u+at
Straight line with positive slope
m⋅s−2m \cdot s^{-2}m⋅s−2
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