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10 questions from this quiz
The rate at which work is done
Transfer of 1 joule of energy per second
P=ΔEΔtP = \frac{\Delta E}{\Delta t}P=ΔtΔE
ΔE=PΔt\Delta E = P\Delta tΔE=PΔt
Power
P=FvcosθP = Fv\cos\thetaP=Fvcosθ
100 J
Power decreases
Increases with square of velocity
Total energy transferred
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