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10 questions from this quiz
p⃗=mv⃗\vec{p} = m\vec{v}p=mv
kg⋅m⋅s−1\text{kg} \cdot \text{m} \cdot \text{s}^{-1}kg⋅m⋅s−1
Vector quantity
1.0 kg⋅m⋅s−11.0 \text{ kg} \cdot \text{m} \cdot \text{s}^{-1}1.0 kg⋅m⋅s−1
F⃗net=Δp⃗Δt\vec{F}_{\text{net}} = \frac{\Delta \vec{p}}{\Delta t}Fnet=ΔtΔp
Total momentum in isolated system is constant
Δp⃗B=−Δp⃗A\Delta \vec{p}_B = -\Delta \vec{p}_AΔpB=−ΔpA
Separately in x and y directions
In isolated systems with no external forces
Same direction as the object's velocity
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