The Electrostatic Force and the Electric Field (HSC SSCE Physics): Quizzes

$\vec{E} = \frac{\vec{F}}{q}$

$1.6 \times 10^{-19}$ C

N C$^{-1}$ (newtons per coulomb)

$\vec{F} = Eq$

It reduces to one-ninth

$9.0 \times 10^{9}$ N m$^{2}$ C$^{-2}$

$F = \frac{1}{4\pi\varepsilon_0}\frac{q_1q_2}{r^2}$

$-1.6 \times 10^{-19}$ C

They repel each other

$\vec{a} = \frac{Eq}{m}$