Relativistic Mass and Momentum (HSC SSCE Physics): Quizzes

Mass measured when object is at rest

$m = \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}}$

It increases dramatically

$1.1 \times 10^{-30}$ kg

98% of $c$ ($2.94 \times 10^8$ m/s)

$p = \frac{m_0 v}{\sqrt{1 - \frac{v^2}{c^2}}}$

Mass increase makes acceleration approach 0

It decreases as $a = \frac{F_R}{\gamma m}$

Circular accelerators using E&M fields

27 kilometres