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In one species of squirrel, Sciurus carolinensis, fur colour is controlled by one gene, with two codominant alleles - AQA - A-Level Biology - Question 1 - 2021 - Paper 1

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In one species of squirrel, Sciurus carolinensis, fur colour is controlled by one gene, with two codominant alleles. C^G represents the allele for grey fur colour, a... show full transcript

Worked Solution & Example Answer:In one species of squirrel, Sciurus carolinensis, fur colour is controlled by one gene, with two codominant alleles - AQA - A-Level Biology - Question 1 - 2021 - Paper 1

Step 1

Use the Hardy-Weinberg equation to estimate how many squirrels in this population had brown-black fur.

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Answer

To estimate how many squirrels had brown-black fur, we first identify the alleles present. Since there are three genotypes (C^G C^G for grey, C^G C^B for brown-black, and C^B C^B for black), we can define the frequencies of the alleles.

Let p represent the frequency of C^G and q represent the frequency of C^B. We know from the problem that:

  • Total squirrels (N) = 34
  • Number of squirrels with black fur = 2

Using the Hardy-Weinberg equation:

We have:

p2+2pq+q2=1p^2 + 2pq + q^2 = 1 (with p^2 being grey, 2pq being brown-black, and q^2 being black).

Given q^2 = 2/34, we find q = sqrt{(2/34)} = approximately 0.243.

Thus, q ≈ 0.24 and p = 1 - q ≈ 0.76

Now we can find the expected number of brown-black squirrels:

2pq=2(0.76)(0.24)imes3416.316squirrels. 2pq = 2(0.76)(0.24) imes 34 ≈ 16.3 \Rightarrow ≈ 16 squirrels.

Step 2

Use all of the information to calculate the actual frequency of the C^G allele.

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The actual number of squirrels is given as:

  • Brown-black fur = 16
  • Total squirrels = 34

To find the actual frequency of the C^G allele:

We use the formula:

frequency=number of allelestotal allelesfrequency = \frac{number \ of \ alleles}{total \ alleles}.

Each squirrel has 2 alleles, hence total alleles = 34 * 2 = 68.

The number of C^G alleles can be calculated as:

Number of CG=(TotalBlack)+(Brownblackcountssincetheyhaveoneofeach)=(342)+16=48.Number \ of \ C^G = (Total - Black) + (Brown-black counts since they have one of each) = (34 - 2) + 16 = 48.

Thus, the frequency of C^G = \frac{number \ of \ C^G}{total \ alleles} = \frac{48}{68} = 0.71 ≈ 0.71.

Step 3

Deductions based on available information.

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Given that S. carolinensis from both regions show the same variation and that an identical black fur mutation exists in related species, the most likely conclusion is:

B. The mutation that caused black fur happened in a common ancestor of S. carolinensis and other closely related species.

Step 4

Calculate the percentage reduction in size of the protein coded for by the C^B allele.

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The length of the protein for the C^G allele is 306 amino acids long.

To calculate the percentage reduction:

Percentage reduction=((306X)306)×100Percentage \ reduction = \left( \frac{(306 - X)}{306} \right) \times 100

Let’s assume that X is the protein length after going through mutation. Without loss of generality, let’s calculate as:

Reduction=(306(30624))/306=24306×1007.84to 3 significant figures, 7.84%.Reduction = (306 - (306 - 24))/306 = \frac{24}{306} \times 100 \approx 7.84 \Rightarrow \text{to 3 significant figures, } 7.84\%.

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