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Figure 1 shows the graph of $y = |2x|$ - AQA - A-Level Maths Mechanics - Question 4 - 2021 - Paper 2

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Figure 1 shows the graph of $y = |2x|$. 4 (a) On Figure 1 add a sketch of the graph of $y = |3x - 6|$. 4 (b) Find the coordinates of the points of intersection of ... show full transcript

Worked Solution & Example Answer:Figure 1 shows the graph of $y = |2x|$ - AQA - A-Level Maths Mechanics - Question 4 - 2021 - Paper 2

Step 1

4 (a) On Figure 1 add a sketch of the graph of $y = |3x - 6|$.

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Answer

To sketch the graph of y=3x6y = |3x - 6|, we start by identifying the vertex of the V shape.

Setting the expression inside the absolute value to zero: egin{align*} 3x - 6 &= 0 \ 3x &= 6 \ x &= 2 \\ ext{Thus, the vertex is at } (2, 0). \end{align*}

Next, we determine the direction of the arms of the V shape. As 3x3x is positive for x>2x > 2, the line has a positive slope to the right (slope of 3), and as xx approaches negative infinity, the 6-6 shifts the graph downwards. Therefore, the graph increases to the left in a symmetric manner. Finally, sketching this onto Figure 1, we ensure the V-shape intersects the y-axis at: y=3(0)6=6=6.y = |3(0) - 6| = | -6 | = 6.

This shows that the graph intersects the y-axis at (0, 6) and is symmetric about the line x = 2.

Step 2

4 (b) Find the coordinates of the points of intersection of the two graphs.

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Answer

To find the points of intersection, we set the equations equal to each other: 2x=3x6.|2x| = |3x - 6|.

This leads us to consider two cases based on the definitions of absolute values:

Case 1: 2x=3x62x = 3x - 6

  1. Rearranging gives: 6=3x2x6 = 3x - 2x
    so, x=6.x = 6.
    Substituting back into y=2xy = |2x|:
    y=2(6)=12.y = |2(6)| = 12.
    Thus, one point of intersection is (6, 12).

Case 2: 2x=(3x6)2x = -(3x - 6)

  1. Rearranging gives: 2x=3x+62x = -3x + 6
    which simplifies to: 5x=6,5x = 6,
    so, x=1.2.x = 1.2.
    Substituting back into y=2xy = |2x|:
    y=2(1.2)=2.4.y = |2(1.2)| = 2.4.
    Thus, the second point of intersection is (1.2, 2.4).

Conclusion

The coordinates of the points of intersection are (6, 12) and (1.2, 2.4).

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